JEE Mains · Physics · STD 11 - 4.2 friction
In the given figure the blocks \(A , B\) and C weigh \(4 kg, 6 kg\) and 8 kg respectively. The co-efficient of sliding friction between any two surfaces is 0.5 . The force \(\overrightarrow{ F }\) required to slide the block C with constant speed is _________ N . (Used \(g =10 m / s ^2\) )
- A 150
- B 210
- C 180
- D 250
Answer & Solution
Correct Answer
(B) 210
Step-by-step Solution
Detailed explanation
For 8 kg to move with constant velocity \(F _{\text {net }}=0\). \(\therefore F =90+ T +50\) (for 8kg block) \(T =20+50\) (for 6 kg block ) \(\therefore F =210 N\).
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