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JEE Mains · Physics · STD 12 - Electromagnetic waves
  • JEE Mains 2019
  • Medium
  • MCQ

The energy associated with electric field is \((U_E)\) and with magnetic field is \((U_B)\) for an electromagnetic wave in free space. Then

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Answer & Solution

Correct Answer

(D) \(U_E\,=\,U_B\)

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\(\mathrm{B}=\frac{\mathrm{E}}{\mathrm{C}}\)

\(\Rightarrow  \mathrm{U}_{\mathrm{E}}=\frac{1}{2} \varepsilon_{\mathrm{o}} \mathrm{E}^{2}\)

\(\mathrm{U}_{\mathrm{B}}=\frac{\mathrm{B}^{2}}{2 \mu_{0}}=\frac{\mathrm{E}^{2}}{2 \mu_{0} \mathrm{C}^{2}}=\frac{\mathrm{E}^{2}}{2 \mu_{0}}\left(\mu_{0} \varepsilon_{0}\right)=\mathrm{U}_{\mathrm{E}}\)

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