JEE Mains · Physics · STD 11 - Oscillations
- JEE Mains 2013
- Medium
- MCQ
The amplitude of a damped oscillator decreases to \(0.9\) times its original magnitude in \(5\ s\). In another \(10\ s\) it will decrease to \(\alpha \) times its original magnitude, where \(\alpha \) equals
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(0.73\)
Step-by-step Solution
Detailed explanation
\(\because A=A_{0} e^{-\frac{b t}{2 m}}\left(\text { where }, A_{0}=\text { maximum amplitude }\right)\)
\( According \,to \,the\, questions,\, after\, 5\, second, \)
\(0.9 \mathrm{A}_{0}=\mathrm{A}_{0} \mathrm{e}^{-\frac{\mathrm{b}(5)}{2 \mathrm{m}}}\) \(...(i)\)
\(After\, 10 \,more\, second,\)
\(A=A_{0} \mathrm{e}^{-\frac{\mathrm{b}(15)}{2 \mathrm{m}}}\) \(...(ii)\)
From eq"s \((i)\) and \((ii)\)
\(A=0.729 A_{0} \therefore \alpha=0.729\)
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