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JEE Mains · Physics · STD 11 - Oscillations
  • JEE Mains 2013
  • Medium
  • MCQ

The amplitude of a damped oscillator decreases to \(0.9\) times its original magnitude in \(5\ s\). In another \(10\ s\) it will decrease to \(\alpha \) times its original magnitude, where  \(\alpha \) equals

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Answer & Solution

Correct Answer

(D) \(0.73\)

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\(\because A=A_{0} e^{-\frac{b t}{2 m}}\left(\text { where }, A_{0}=\text { maximum amplitude }\right)\)

\( According \,to \,the\, questions,\, after\, 5\, second, \)

\(0.9 \mathrm{A}_{0}=\mathrm{A}_{0} \mathrm{e}^{-\frac{\mathrm{b}(5)}{2 \mathrm{m}}}\)                        \(...(i)\)

\(After\, 10 \,more\, second,\)

\(A=A_{0} \mathrm{e}^{-\frac{\mathrm{b}(15)}{2 \mathrm{m}}}\)            \(...(ii)\)

From eq"s \((i)\) and \((ii)\) 

\(A=0.729 A_{0} \therefore \alpha=0.729\)

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