JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
Consider a uniform rod of mass \(\mathrm{M}=4 \mathrm{m}\) and length \(\ell\) pivoted about its centre. A mass \(m\) moving with velocity \(v\) making angle \(\theta=\frac{\pi}{4}\) to the rod's long axis collides with one end of the rod and sticks to it. The angular speed of the rod-mass system just after the collision is
- A \(\frac{3}{7 \sqrt{2}} \frac{\mathrm{v}}{l}\)
- B \(\frac{3 \sqrt{2}}{7} \frac{v}{l}\)
- C \(\frac{4}{7} \frac{v}{l}\)
- D \(\frac{3}{7} \frac{v}{l}\)
Answer & Solution
Correct Answer
(B) \(\frac{3 \sqrt{2}}{7} \frac{v}{l}\)
Step-by-step Solution
Detailed explanation
Let angular velocity of the system after collision be \(\omega\). By conservation of angular momentum about the hinge…
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