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JEE Mains · Physics · STD 11 - System of particles and rotational motion
  • JEE Mains 2025
  • Medium
  • MCQ

A rod of length 5 L is bent right angle keeping one side length as 2 L.

The position of the centre of mass of the system: (Consider \(\mathrm{L}=10 \mathrm{~cm}\))

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Answer & Solution

Correct Answer

(D) \(4 \hat{i}+9 \hat{j}\)

Step-by-step Solution

Detailed explanation


\(\mathrm{x}_{\mathrm{com}}=\frac{2 \mathrm{~m}(10)+3 \mathrm{~m}(0)}{5 \mathrm{~m}}=4 \mathrm{~cm}\)
\(\mathrm{y}_{\mathrm{com}}=\frac{2 \mathrm{~m}(0)+3 \mathrm{~m}(15)}{5 \mathrm{~m}}=9 \mathrm{~cm}\)
\(\overrightarrow{\mathrm{r}}_{\mathrm{com}}=4 \hat{\mathrm{i}}+9 \hat{\mathrm{j}}\)
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