JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
A rod of length 5 L is bent right angle keeping one side length as 2 L.

The position of the centre of mass of the system: (Consider \(\mathrm{L}=10 \mathrm{~cm}\))
- A \(2 \hat{i}+3 \hat{j}\)
- B \(3 \hat{i}+7 \hat{\mathrm{j}}\)
- C \(5 \hat{\mathrm{i}}+8 \hat{\mathrm{j}}\)
- D \(4 \hat{i}+9 \hat{j}\)
Answer & Solution
Correct Answer
(D) \(4 \hat{i}+9 \hat{j}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{x}_{\mathrm{com}}=\frac{2 \mathrm{~m}(10)+3 \mathrm{~m}(0)}{5 \mathrm{~m}}=4 \mathrm{~cm}\) \(\mathrm{y}_{\mathrm{com}}=\frac{2 \mathrm{~m}(0)+3 \mathrm{~m}(15)}{5 \mathrm{~m}}=9 \mathrm{~cm}\)…
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