JEE Mains · Physics · STD 11 - 11. thermodynamics
\(1\,g\) of a liquid is converted to vapour at \(3 \times 10^5\,Pa\) pressure. If \(10 \%\) of the heat supplied is used for increasing the volume by \(1600\,cm ^3\) during this phase change, then the increase in internal energy in the process will be \(............\,J\)
- A \(4320\)
- B \(432000\)
- C \(4800\)
- D \(4.32\)
Answer & Solution
Correct Answer
(A) \(4320\)
Step-by-step Solution
Detailed explanation
Work done \(= P \Delta V\) \(=3 \times 10^5 \times 1600 \times 10^{-6}\) \(=480\,J\) Only \(10 \%\) of heat is used in work done. Hence \(\Delta Q=4800\,J\) The rest goes in internal energy, which is \(90\,\%\) of heat. Change in internal energy \(=0.9 \times 4800=4320\,J\)
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