JEE Mains · Physics · STD 11 - Units,dimensions and measurement
- JEE Mains 2020
- Hard
- MCQ
A quantity \(x\) is given by \(\left( IF v^{2} / WL ^{4}\right)\) in terms of moment of inertia \(I,\) force \(F\), velocity \(v\), work \(W\) and Length \(L\). The dimensional formula for \(x\) is same as that of
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Answer & Solution
Correct Answer
(C) Energy density
Step-by-step Solution
Detailed explanation
\(x=\frac{I F V^{2}}{W L^{4}}\)
\([ x ]=\frac{\left[ ML ^{2}\right]\left[ MI T ^{-2}\right]\left[ L T ^{-1}\right]^{2}}{\left[ ML ^{2} T ^{-2}\right][ L ]^{4}}\)
\([ x ]=\left[ ML ^{-1} T ^{-2}\right]\)
[Energy density] \(=\left[\frac{ E }{ V }\right]\)
\(=\left[\frac{M L^{2} T^{-2}}{L^{3}}\right]\)
\(=\left[ ML ^{-1} T ^{-2}\right]\)
Same as \(x\)
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