JEE Mains · Physics · STD 11 - 7. gravitation
The mass and the diameter of a planet are three times the respective values for the Earth. The period of oscillation of a simple pendulum on the Earth is \(2\,s\). The period of oscillation of the same pendulum on the planet would be
- A \(\frac{{\sqrt 3 }}{2}\,s\)
- B \(\frac{2}{{\sqrt 3 }}\,s\)
- C \(\frac{3}{2}\,s\)
- D \(2\sqrt 3 \,s\)
Answer & Solution
Correct Answer
(D) \(2\sqrt 3 \,s\)
Step-by-step Solution
Detailed explanation
\(g = \frac{{GM}}{{{R^2}}}\) \(\frac{{{g_p}}}{{{g_e}}} = \frac{{{M_p}}}{{{M_e}}}{\left( {\frac{{{R_e}}}{{{R_p}}}} \right)^2} = 3{\left( {\frac{1}{3}} \right)^2} = \frac{1}{3}\) \(Also,\,T \propto \frac{1}{{\sqrt g }}\)…
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