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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2023
  • Easy
  • Numerical

An organ pipe \(40\,cm\) long is open at both ends. The speed of sound in air is \(360\,ms ^{-1}\). The frequency of the second harmonic is \(...........\,Hz\).

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Answer & Solution

Correct Answer

(B) \(900\)

Step-by-step Solution

Detailed explanation

For second harmonic of open organ pipe

\(L =\lambda\)

So frequency of vibration is \(f =\frac{ V }{\lambda}\)

\(f =\frac{ V }{\lambda}=\frac{ V }{ L }=\frac{360}{\frac{40}{100}}=900\,Hz\)

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