JEE Mains · Physics · STD 11 - Waves and sound
- JEE Mains 2023
- Easy
- Numerical
An organ pipe \(40\,cm\) long is open at both ends. The speed of sound in air is \(360\,ms ^{-1}\). The frequency of the second harmonic is \(...........\,Hz\).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(900\)
Step-by-step Solution
Detailed explanation
For second harmonic of open organ pipe
\(L =\lambda\)
So frequency of vibration is \(f =\frac{ V }{\lambda}\)
\(f =\frac{ V }{\lambda}=\frac{ V }{ L }=\frac{360}{\frac{40}{100}}=900\,Hz\)
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