JEE Mains · Physics · STD 11 - 14. waves and sound
An organ pipe \(40\,cm\) long is open at both ends. The speed of sound in air is \(360\,ms ^{-1}\). The frequency of the second harmonic is \(...........\,Hz\).
- A \(800\)
- B \(900\)
- C \(700\)
- D \(600\)
Answer & Solution
Correct Answer
(B) \(900\)
Step-by-step Solution
Detailed explanation
For second harmonic of open organ pipe \(L =\lambda\) So frequency of vibration is \(f =\frac{ V }{\lambda}\) \(f =\frac{ V }{\lambda}=\frac{ V }{ L }=\frac{360}{\frac{40}{100}}=900\,Hz\)
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