JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
Two insulated circular loop \(A\) and \(B\) radius ' \(a\) ' carrying a current of ' \(\mathrm{I}\) ' in the anti clockwise direction as shown in figure. The magnitude of the magnetic induction at the centre will be _______.
- A \(\frac{\sqrt{2} \mu_0 I}{a}\)
- B \(\frac{\mu_0 I}{2 a}\)
- C \(\frac{\mu_0 I}{\sqrt{2} a}\)
- D \(\frac{2 \mu_0 I}{a}\)
Answer & Solution
Correct Answer
(C) \(\frac{\mu_0 I}{\sqrt{2} a}\)
Step-by-step Solution
Detailed explanation
\(\because B_{n e t}=\frac{\sqrt{2} \mu_0 I}{2 a}\)
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