JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2024
- Hard
- Numerical
To determine the resistance (\(R\)) of a wire, a circuit is designed below, The \(V-I\) characteristic curve for this circuit is plotted for the voltmeter and the ammeter readings as shown in figure. The value of \(\mathrm{R}\) is _______\(\Omega\).

Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(2500\)
Step-by-step Solution
Detailed explanation
\(\text { Req }=\frac{10^4 R}{10^4+R}\)
\(E=4 V, I=2 m A\)
\(I=\frac{E}{R e q} \Rightarrow 2 \times 10^{-3}=\frac{4\left(10^4+R\right)}{10^4 R}\)
\(\Rightarrow 20 R=40000+4 R\)
\(\quad 16 R=40000\)
\(R=2500 \Omega\)
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