JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
The momentum of a body is increased by \(50 \%\). The percentage increase in the kinetic energy of the body is \(...........\,\%\)
- A \(124\)
- B \(125\)
- C \(123\)
- D \(122\)
Answer & Solution
Correct Answer
(B) \(125\)
Step-by-step Solution
Detailed explanation
Kinetic energy of body \(=\frac{p^2}{2 m}\) Initial kinetic energy \(=\frac{p_1^2}{2 m }\) Final kinetic energy \(=\frac{p_f^2}{2 m }=\frac{\left(1.5 p _{ i }\right)^2}{2 m }\) \(=\frac{2.25 p _{ i }^2}{2 m }\) \(\%\) increase in…
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