JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
The \(X-Y\) plane be taken as the boundary between two transparent media \(M _{1}\) and \(M _{2} . M _{1}\) in \(Z \geq 0\) has a refractive index of \(\sqrt{2}\) and \(M _{2}\) with \(Z <0\) has a refractive index of \(\sqrt{3}\). A ray of light travelling in \(M_{1}\) along the direction given by the vector \(\overrightarrow{ A }=4 \sqrt{3 i }-3 \sqrt{3 \hat{j}}-5 \hat{ k }\), is incident on the plane of separation. The value of difference between the angle of incident in \(M _{1}\) and the angle of refraction in \(M _{2}\) will be \(....\) degree.
- A \(7\)
- B \(15\)
- C \(254\)
- D \(225\)
Answer & Solution
Correct Answer
(B) \(15\)
Step-by-step Solution
Detailed explanation
\(\overrightarrow{ A }=4 \sqrt{3 \hat{i}}-3 \sqrt{3 \hat{j}}-5 \hat{ k }\) As incident vector \(A\) makes \(i\) angle with normal \(z-\)axis refracted vector \(R\) makes \(r\) angle with normal \(z\) - axis with help of direction cosine…
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