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JEE Mains · Physics · STD 11 - Kinetic theory of gases
  • JEE Mains 2019
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  • MCQ

\(2\, kg\) of a monoatomic gas is at a pressure of \(4\times10^4\, N/m^2\). The density of the gas is \(8\, kg/m^3\). What is the order of energy of the gas due to its thermal motion ?

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Correct Answer

(C) \(10^4\, J\)

Step-by-step Solution

Detailed explanation

\(\mathrm{E} =\frac{1}{2} \mathrm{M} \mathrm{V}_{m}^{2} \)

\(=\frac{1}{2} \times 2 \times\left(\frac{3 \mathrm{P}}{\rho}\right) \)

\(=\frac{3 \times 4 \times 10^{4}}{8}=1.5 \times 10^{4} \mathrm{J}\)

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