JEE Mains · Physics · STD 11 - Kinetic theory of gases
- JEE Mains 2019
- Medium
- MCQ
\(2\, kg\) of a monoatomic gas is at a pressure of \(4\times10^4\, N/m^2\). The density of the gas is \(8\, kg/m^3\). What is the order of energy of the gas due to its thermal motion ?
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Answer & Solution
Correct Answer
(C) \(10^4\, J\)
Step-by-step Solution
Detailed explanation
\(\mathrm{E} =\frac{1}{2} \mathrm{M} \mathrm{V}_{m}^{2} \)
\(=\frac{1}{2} \times 2 \times\left(\frac{3 \mathrm{P}}{\rho}\right) \)
\(=\frac{3 \times 4 \times 10^{4}}{8}=1.5 \times 10^{4} \mathrm{J}\)
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