JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
\(2\, kg\) of a monoatomic gas is at a pressure of \(4\times10^4\, N/m^2\). The density of the gas is \(8\, kg/m^3\). What is the order of energy of the gas due to its thermal motion ?
- A \(10^3\, J\)
- B \(10^5\, J\)
- C \(10^4\, J\)
- D \(10^6\, J\)
Answer & Solution
Correct Answer
(C) \(10^4\, J\)
Step-by-step Solution
Detailed explanation
\(\mathrm{E} =\frac{1}{2} \mathrm{M} \mathrm{V}_{m}^{2} \) \(=\frac{1}{2} \times 2 \times\left(\frac{3 \mathrm{P}}{\rho}\right) \) \(=\frac{3 \times 4 \times 10^{4}}{8}=1.5 \times 10^{4} \mathrm{J}\)
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