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JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments

Time taken by light to travel in two different materials \(A\) and \(B\) of refractive indices \(\mu_{A}\) and \(\mu_{B}\) of same thickness is \(t_{1}\) and \(t_{2}\) respectively. If \(t_{2}-t_{1}=5 \times 10^{-10}\) s and the ratio of \(\mu_{A}\) to \(\mu_{B}\) is \(1: 2\). Then the thickness of material, in meter is: (Given \(v_{A}\) and \(v_{B}\) are velocities of light in \(A\) and \(B\) materials respectively).

  1. A \(5 \times 10^{-10}\,v _{ a } m\)
  2. B \(5 \times 10^{-10}\,m\)
  3. C \(1.5 \times 10^{10}\,m\)
  4. D \(5 \times 10^{-10} v _{ B }\,m\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(5 \times 10^{-10}\,v _{ a } m\)

Step-by-step Solution

Detailed explanation

\(\frac{\mu_{ A }}{\mu_{ B }}=\frac{ c / V _{ A }}{ c / V _{ B }}=\frac{ V _{ B }}{ V _{ A }}=\frac{1}{2}\) Let the thickness is \(d\) \(\frac{d}{v_{B}}-\frac{d}{v_{A}}=5 \times 10^{-10}\) \(d =\frac{5 \times 10^{-10} \times v _{ A } v _{ B }}{ v _{ A }- v _{ B }}\) As…
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