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JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance

A three coulomb charge moves from the point \((0, -2, -5)\) to the point \((5, 1, 2)\) in an electric field expressed as \(\vec{E} = 2x\hat{i} + 3y^2\hat{j} + 4\hat{k}\) N/C. The work done in moving the charge is _______ J.

  1. A 180
  2. B 182
  3. C 184
  4. D 186
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Answer & Solution

Correct Answer

(D) 186

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Detailed explanation

The force experienced by the charge in the electric field is given by \(\vec{F} = q\vec{E}\). Given \(q = 3\) C and \(\vec{E} = 2x\hat{i} + 3y^2\hat{j} + 4\hat{k}\) N/C, the force is: \(\vec{F} = 3(2x\hat{i} + 3y^2\hat{j} + 4\hat{k}) = 6x\hat{i} + 9y^2\hat{j} + 12\hat{k}\) N The…
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