JEE Mains · Physics · STD 11 - 11. thermodynamics
The internal energy of a monoatomic gas is 3 nRT . One mole of helium is kept in a cylinder having internal cross section area of \(17 cm^2\) and fitted with a light movable frictionless piston. The gas is heated slowly by suppling 126 J heat. If the temperature rises by \(4^{\circ} C\), then the piston will move ___________ cm.
(atmospheric pressure \(=10^5 Pa\) )
- A 14.5
- B 1.55
- C 15.5
- D 1.45
Answer & Solution
Correct Answer
(C) 15.5
Step-by-step Solution
Detailed explanation
\(\Delta U=3nR\Delta T\) \(\Delta U=3\times1\times\frac{25}{3}\times4=100~Joule\) \(\Delta Q=126\) \(W=26=P\Delta V\) \(26=10^{3}\times17\times10^{-4}\Delta x\) \(\Delta x=\frac{26}{170}=15.3\)
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