JEE Mains · Physics · STD 12 - Magnetism and matter
- JEE Mains 2022
- Medium
- MCQ
A magnet hung at \(45^{\circ}\) with magnetic meridian makes an angle of \(60^{\circ}\) with the horizontal. The actual value of the angle of dip is.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(\tan ^{-1}\left(\sqrt{\frac{3}{2}}\right)\)
Step-by-step Solution
Detailed explanation
\(\tan \theta^{\prime}=\frac{\tan \theta}{\cos \alpha}\)
\(\theta^{\prime}=60^{\circ}\)
\(\alpha=45^{\circ}\)
\(\sqrt{3}=\frac{\tan \theta}{\frac{1}{\sqrt{2}}}\)
\(\tan \theta=\sqrt{\frac{3}{2}}\)
\(\theta=\tan ^{-1} \sqrt{\frac{3}{2}}\)
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