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JEE Mains · Physics · STD 12 - Magnetism and matter
  • JEE Mains 2022
  • Medium
  • MCQ

A magnet hung at \(45^{\circ}\) with magnetic meridian makes an angle of \(60^{\circ}\) with the horizontal. The actual value of the angle of dip is.

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Answer & Solution

Correct Answer

(A) \(\tan ^{-1}\left(\sqrt{\frac{3}{2}}\right)\)

Step-by-step Solution

Detailed explanation

\(\tan \theta^{\prime}=\frac{\tan \theta}{\cos \alpha}\)

\(\theta^{\prime}=60^{\circ}\)

\(\alpha=45^{\circ}\)

\(\sqrt{3}=\frac{\tan \theta}{\frac{1}{\sqrt{2}}}\)

\(\tan \theta=\sqrt{\frac{3}{2}}\)

\(\theta=\tan ^{-1} \sqrt{\frac{3}{2}}\)

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