JEE Mains · Physics · STD 12 - Nuclei
- JEE Mains 2021
- Hard
- Numerical
The half-life of \(Au ^{198}\) is \(2.7\, days.\) The activity of \(1.50\, mg\) of \(Au ^{198}\) if its atomic weight is \(198\, g mol ^{-1}\) is .......\(Ci\) \(\left( N _{ A }=6 \times 10^{23}\, / mol \right)\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(357\)
Step-by-step Solution
Detailed explanation
\(A =\lambda N\)
\(N = nN _{ A }\)\(\quad\left( t _{1 / 2}=\frac{\ln 2}{\lambda}\right)\)
\(N =\left(\frac{1.5 \times 10^{-3}}{198}\right) N _{ A }\)
\(A=\left(\frac{\ln 2}{t_{1 / 2}}\right) N\)
\(1\) Curie \(=3.7 \times 10^{10}\, Bq\)
\(A =365\, Bq\)
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