JEE Mains · Physics · STD 11 - 2. motion in straight line
The velocity-time graphs of a car and a scooter are shown in the figure. \((i)\) the difference between the distance travelled by the car and the scooter in \(15\, s\) and \((ii)\) the time at which the car will catch up with the scooter are, respectively
- A \(337.5\,m\) and \(25\,s\)
- B \(225.5\,m\) and \(10\,s\)
- C \(112.5\,m\) and \(22.5\,s\)
- D \(112.5\,m\) and \(15\,s\)
Answer & Solution
Correct Answer
(C) \(112.5\,m\) and \(22.5\,s\)
Step-by-step Solution
Detailed explanation
Using equation, \(a=\frac{v-u}{t}\) and \(s=u t+\frac{1}{2} a t^2\) Distance travelled by car in 15 sec \(=\frac{1}{2} \frac{(45)}{15}(15)^2\) \(=\frac{675}{2} m\) Distance traveled by scooter in 15 seconds…
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