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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter

The de Broglie wavelength for an electron accelerated through the potential difference of \(V_1\) volt is \(\lambda_1\). When the potential difference is changed to \(V_2\) volt, the associated de Broglie wavelength is increased by \(50\%\). If \((V_1/V_2) = (9/\alpha)\), then the value of \(\alpha\) is __________.

  1. A 1
  2. B 2
  3. C 3
  4. D 4
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(D) 4

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The de Broglie wavelength of an electron accelerated through a potential difference \(V\) is given by \(\lambda = \dfrac{h}{\sqrt{2meV}}\). This implies \(\lambda \propto \dfrac{1}{\sqrt{V}}\). Given that the new wavelength \(\lambda_2\) is increased by \(50\%\), we have…
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