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JEE Mains · Physics · STD 11 - Motion in straight line
  • JEE Mains 2018
  • Medium
  • Numerical

An automobile, travelling at \(40\, km/h\), can be stopped at a distance of \(40\, m\) by applying brakes. If the same automobile is travelling at \(80\, km/h\), the minimum stopping distance, in metres, is (assume no skidding)..........\(m\)

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Answer & Solution

Correct Answer

(B) \(160\)

Step-by-step Solution

Detailed explanation

\(\begin{array}{l}
According\,to\,question,\,{u_1} = 40\,km/h,\,{v_1} = 0\\
and\,{s_1} = 40\,m\\
{\rm{using}}\,{{\rm{v}}^2} - {u^2} = 2as;\,{0^2} - {40^2} = 2a \times 40\,\,\,\,\,\,...\left( i \right)\\
Again,\,{0^2} - {80^2} = 2as\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...\left( {ii} \right)\\
From\,eqn.\left( i \right)\,and\,\left( {ii} \right)\,\\
Stopping\,{\rm{ distance}},\,s = 160\,m\,\,
\end{array}\)
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