JEE Mains · Physics · STD 11 - 2. motion in straight line
An automobile, travelling at \(40\, km/h\), can be stopped at a distance of \(40\, m\) by applying brakes. If the same automobile is travelling at \(80\, km/h\), the minimum stopping distance, in metres, is (assume no skidding)..........\(m\)
- A \(75\)
- B \(160\)
- C \(100\)
- D \(150\)
Answer & Solution
Correct Answer
(B) \(160\)
Step-by-step Solution
Detailed explanation
\begin{array}{l} According\,to\,question,\,{u_1} = 40\,km/h,\,{v_1} = 0\\ and\,{s_1} = 40\,m\\ {\rm{using}}\,{{\rm{v}}^2} - {u^2} = 2as;\,{0^2} - {40^2} = 2a \times 40\,\,\,\,\,\,...\left( i \right)\\ Again,\,{0^2} - {80^2} =…
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