JEE Mains · Physics · STD 12 - Semicondutor electronics
- JEE Mains 2024
- Hard
- MCQ
The output of the given circuit diagram is _______.

Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(A\) \(B\) \(Y\) \(0\) \(0\) \(0\) \(1\) \(0\) \(0\) \(0\) \(1\) \(0\) \(1\) \(1\) \(0\)
Step-by-step Solution
Detailed explanation
\(\text { If } \mathrm{A}=0 ; \overline{\mathrm{A}}=1\)
\(\mathrm{~A}=1 ; \overline{\mathrm{A}}=0\)
\(\mathrm{~B}=0 ; \overline{\mathrm{B}}=1\)
\(\mathrm{~B}=1 ; \overline{\mathrm{B}}=0\)
\(\mathrm{Y}=\overline{(\mathrm{A}+\overline{\mathrm{B}})+(\overline{\mathrm{A}}+\mathrm{B})}=\overline{(1+1)}=0\)

\(\mathrm{~A}=1 ; \overline{\mathrm{A}}=0\)
\(\mathrm{~B}=0 ; \overline{\mathrm{B}}=1\)
\(\mathrm{~B}=1 ; \overline{\mathrm{B}}=0\)
\(\mathrm{Y}=\overline{(\mathrm{A}+\overline{\mathrm{B}})+(\overline{\mathrm{A}}+\mathrm{B})}=\overline{(1+1)}=0\)

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