JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
The mean free path of molecules of a certain gas at \(STP\) is \(1500\,d\), where \(d\) is the diameter of the gas molecules. While maintaining the standard pressure, the mean free path of the molecules at \(373\,K\) is approximately \(..........\,d\)
- A \(1098\)
- B \(2049\)
- C \(750\)
- D \(1500\)
Answer & Solution
Correct Answer
(B) \(2049\)
Step-by-step Solution
Detailed explanation
Mean free path \(\lambda=\frac{ RT }{\sqrt{2} \pi d ^2 N _{ A } P }\) \(\lambda \propto T\) \(\frac{1500 d }{\lambda}=\frac{273}{373}\) \(\lambda=2049\,d\)
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