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JEE Mains · Physics · STD 11 - Kinetic theory of gases
  • JEE Mains 2023
  • Medium
  • Numerical

The mean free path of molecules of a certain gas at \(STP\) is \(1500\,d\), where \(d\) is the diameter of the gas molecules. While maintaining the standard pressure, the mean free path of the molecules at \(373\,K\) is approximately \(..........\,d\)

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Answer & Solution

Correct Answer

(B) \(2049\)

Step-by-step Solution

Detailed explanation

Mean free path

\(\lambda=\frac{ RT }{\sqrt{2} \pi d ^2 N _{ A } P }\)

\(\lambda \propto T\)

\(\frac{1500 d }{\lambda}=\frac{273}{373}\)

\(\lambda=2049\,d\)

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