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JEE Mains · Physics · STD 12 - Moving charges and magnetism
  • JEE Mains 2023
  • Medium
  • MCQ

A circular loop of radius \(r\) is carrying current I A. The ratio of magnetic field at the centre of circular loop and at a distance \(r\) from the center of the loop on its axis is:

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Answer & Solution

Correct Answer

(C) \(2 \sqrt{2}: 1\)

Step-by-step Solution

Detailed explanation

Magnetic field due to current carrying circular loop on its axis is given as

\(\frac{\mu_0 ir ^2}{2\left( r ^2+ x ^2\right)^{3 / 2}}\)

At centre, \(x=0, B_1=\frac{\mu_0 i }{2 r }\)

At \(x=r, B_2=\frac{\mu_0 i}{2 \times 2 \sqrt{2 r}}\)

\(\frac{ B _1}{ B _2}=2 \sqrt{2}\)

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