JEE Mains · Physics · STD 11 - Oscillations
- JEE Mains 2024
- Hard
- Numerical
The time period of simple harmonic motion of mass \(\mathrm{M}\) in the given figure is \(\pi \sqrt{\frac{\alpha M}{5 K}}\), where the value of \(\alpha\) is _______.

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Answer & Solution
Correct Answer
(A) \(12\)
Step-by-step Solution
Detailed explanation
\(\mathrm{k}_{\mathrm{eq}}=\frac{2 \mathrm{k} \cdot \mathrm{k}}{3 \mathrm{k}}+\mathrm{k}=\frac{5 \mathrm{k}}{3}\)
Angular frequency of oscillation \((\omega)=\sqrt{\frac{\mathrm{k}_{\mathrm{eq}}}{\mathrm{m}}}\)
\((\omega)=\sqrt{\frac{5 \mathrm{k}}{3 \mathrm{~m}}}\)
Period of oscillation \((\tau)=\frac{2 \pi}{\omega}=2 \pi \sqrt{\frac{3 \mathrm{~m}}{5 \mathrm{k}}}\)
\(=\pi \sqrt{\frac{12 \mathrm{~m}}{5 \mathrm{k}}}\)
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