JEE Mains · Physics · STD 11 - 13. oscillations
The position, velocity and acceleration of a particle executing simple harmonic motion are found to have magnitudes of \(4 \mathrm{~m}, 2 \mathrm{~ms}^{-1}\) and \(16 \mathrm{~ms}^{-2}\) at a certain instant. The amplitude of the motion is \(\sqrt{\mathrm{x}} \mathrm{m}\) where \(\mathrm{x}\) is _______.
- A \(17\)
- B \(18\)
- C \(19\)
- D \(20\)
Answer & Solution
Correct Answer
(A) \(17\)
Step-by-step Solution
Detailed explanation
\(x=4 \mathrm{~m}, \mathrm{~V}=2 \mathrm{~m} / \mathrm{s}, \mathrm{a}=16 \mathrm{~m} / \mathrm{s}^2\) \(|\mathrm{a}|=\omega^2 \mathrm{x}\) \(\Rightarrow 16=\omega^2(4)\) \(\omega=2 \mathrm{rad} / \mathrm{s}\) \(\mathrm{v}=\omega \sqrt{\mathrm{A}^2-\mathrm{x}^2}\)…
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