JEE Mains · Physics · STD 12 -6. Electromagnetic induction
An inductor of inductance \(10\) mH having resistance of \(100\,\Omega\) is connected to battery of E.M.F. \(1.0\) V through a switch as shown in the figure below. After switch is closed, the ratio of instantaneous voltages across the inductor when the current passing through it is \(2\) mA and \(4\) mA is _______.
- A \(4/3\)
- B \(3/4\)
- C \(5/3\)
- D \(3/5\)
Answer & Solution
Correct Answer
(A) \(4/3\)
Step-by-step Solution
Detailed explanation
In an LR circuit, the equation for the voltage is given by Kirchhoff's loop law: \(E = L \dfrac{di}{dt} + iR\) The instantaneous voltage across the ideal inductor is the induced EMF, which is given by: \(V_L = L \dfrac{di}{dt} = E - iR\) Given values are: \(E = 1.0\) V…
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