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JEE Mains · Physics · STD 11 - Work,energy,power and collision
  • JEE Mains 2021
  • Medium
  • MCQ

A boy is rolling a \(0.5\, kg\) ball on the frictionless floor with the speed of \(20\, ms ^{-1}\). The ball gets deflected by an obstacle on the way. After deflection it moves with \(5 \%\) of its initial kinetic energy. What is the speed of the ball now ? (in \(ms ^{-1}\))

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Answer & Solution

Correct Answer

(B) \(4.47\)

Step-by-step Solution

Detailed explanation

Given, \(m =0.5 kg\) and \(u =20 m / s\)

Initial kinetic energy \(\left( k _{ i }\right)=\frac{1}{2} mu ^{2}\)

\(=\frac{1}{2} \times 0.5 \times 20 \times 20=100 J\)

After deflection it moves with \(5 \%\) of \(k _{ i }\)

\(\therefore k _{ f }=\frac{5}{100} \times k _{ i } \Rightarrow \frac{5}{100} \times 100\)

\(\Rightarrow k_{ f }=5 J\)

Now, let the final speed be 'v' \(m / s\), then :

\(k_{ f }=5=\frac{1}{2} mv ^{2}\)

\(\Rightarrow v ^{2}=20\)

\(\Rightarrow v =\sqrt{20}=4.47 m / s\)

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