JEE Mains · Physics · STD 12 - Electromagnetic waves
- JEE Mains 2025
- Hard
- Numerical
A time varying potential difference is applied between the plates of a parallel plate capacitor of capacitance \(2.5 \mu \mathrm{~F}\). The dielectric constant of the medium between the capacitor plates is 1 . It produces an instantaneous displacement current of 0.25 mA in the intervening space between the capacitor plates, the magnitude of the rate of change of the potential difference will be _____ \(\mathrm{Vs}^{-1}\).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) 100
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \frac{\mathrm{CdV}}{\mathrm{dt}}=\mathrm{I}_{\mathrm{d}} \\ & \frac{\mathrm{dV}}{\mathrm{dt}}=\frac{\mathrm{I}_{\mathrm{d}}}{\mathrm{C}} \\ & =\frac{0.25 \times 10^{-3}}{2.5 \times 10^{-6}} \\ & =100\end{aligned}\)
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