JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
Two closed vessels of same volume are joined through a narrow tube and both vessels are filled with air of pressure \(90\) kPa and temperature \(400\) K. Keeping the temperature of one vessel constant at \(400\) K the second vessel temperature is raised to \(500\) K. The final pressure in the vessels is _______ kPa.
- A \(100\)
- B \(120\)
- C \(90\)
- D \(105\)
Answer & Solution
Correct Answer
(A) \(100\)
Step-by-step Solution
Detailed explanation
Let the volume of each vessel be \(V\). Initially, both vessels are at pressure \(P_1 = 90\) kPa and temperature \(T_1 = 400\) K. Total number of moles initially is given by: \(n_i = \dfrac{P_1 V}{R T_1} + \dfrac{P_1 V}{R T_1} = \dfrac{2 P_1 V}{R T_1}\) Finally, the temperature…
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