JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth is closest to : [Boltzmans Constant \(k_B = 1.38\times10^{-23}\, J / K\) Avogadro number \(N_A = 6.02\times10^{26}\, / kg\) Radius of Earth \(: 6.4\times10^6\, m\) Gravitation acceleration on Earth \(= 10\, ms^{-2}\)]
- A \(800\,K\)
- B \(10^4\,K\)
- C \(3\times10^5\,K\)
- D \(650\,K\)
Answer & Solution
Correct Answer
(B) \(10^4\,K\)
Step-by-step Solution
Detailed explanation
\(v_{m s}=\sqrt{\frac{3 R T}{m}} \quad v_{\text {escape }}=\sqrt{2 g R_{e}}\) \(\mathrm{v}_{\mathrm{rms}}=\mathrm{v}_{\text {escape }}\) \(\frac{3 \mathrm{RT}}{\mathrm{m}}=2 \mathrm{gR}_{\mathrm{e}}\)…
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