JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
The value of the resistor, \(R_S\), needed in the \(dc\) voltage regulator circuit shown here, equals
- A \(\frac{{\left( {{V_i} - {V_L}} \right)}}{{\left( {n + 1} \right){I_L}}}\)
- B \(\frac{{\left( {{V_i} + {V_L}} \right)}}{{\left( {n + 1} \right){I_L}}}\)
- C \(\frac{{\left( {{V_i} - {V_L}} \right)}}{{n{I_L}}}\)
- D \(\frac{{\left( {{V_i} + {V_L}} \right)}}{{n{I_L}}}\)
Answer & Solution
Correct Answer
(A) \(\frac{{\left( {{V_i} - {V_L}} \right)}}{{\left( {n + 1} \right){I_L}}}\)
Step-by-step Solution
Detailed explanation
Voltage on resistor \(R_s\,=\,V_i\,-\,V_L\) or, \(({{I}_{L}}\,+\,n{{I}_{L}}){{R}_{s}}\,=\,{{V}_{i}}\,-\,{{V}_{L}}\) \(\therefore \,\,{{R}_{s}}\,=\,\frac{\,{{V}_{i}}\,-\,{{V}_{L}}}{(n+\,1){{I}_{L}}}\)
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