JEE Mains · Physics · STD 12 -7. Alternating current
Figure shows a circuit that contains four identical resistors with resistance \(R =2.0\, \Omega,\) two identical inductors with inductance \(L =2.0 \,mH\) and an ideal battery with \(e m f E =9 \,V .\) The current \('i'\) just after the switch \('S'\) is closed will be .... \(A\)
- A \(2.25\)
- B \(3.0\)
- C \(3.37\)
- D \(9.0\)
Answer & Solution
Correct Answer
(A) \(2.25\)
Step-by-step Solution
Detailed explanation
Just after the switch is closed, inductor will behave like infinite resistance (open circuit) so the circuit will look like \(i=\frac{9}{R+R}=\frac{9}{4}=2.25\)
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