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JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases

The volume \(V\) of an enclosure contains a mixture of three gases, \(16\, g\) of oxygen, \(28\, g\) of nitrogen and \(44\, g\) of carbon dioxide at absolute temperature \(T\). Consider \(R\) as universal gas constant. The pressure of the mixture of gases is

  1. A \(\frac{88 RT }{ V }\)
  2. B \(\frac{3 RT }{ V }\)
  3. C \(\frac{5}{2} \frac{ RT }{ V }\)
  4. D \(\frac{4 RT }{ V }\)
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Answer & Solution

Correct Answer

(C) \(\frac{5}{2} \frac{ RT }{ V }\)

Step-by-step Solution

Detailed explanation

\(PV =\left( n _{1}+ n _{2}+ n _{3}\right) RT\) \(P \times V =\left[\frac{16}{32}+\frac{28}{28}+\frac{44}{44}\right] RT\) \(PV =\left[\frac{1}{2}+1+1\right] RT\) \(P =\frac{5}{2} \frac{ RT }{ V }\)
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