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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2023
  • Easy
  • Numerical

The number density of free electrons in copper is nearly \(8 \times 10^{28}\,m ^{-3} . A\) copper wire has its area of cross section \(=2 \times 10^{-6}\,m ^2\) and is carrying a current of \(3.2\,A\). The drift speed of the electrons is \(.....\times 10^{-6}\,ms ^{-1}\).

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Answer & Solution

Correct Answer

(A) \(125\)

Step-by-step Solution

Detailed explanation

\(n =8 \times 10^{28}\,m ^{-3}\)

Area \(=2 \times 10^{-6}\,m ^2\)

\(I=3.2\,A\)

\(I = neAv_{d }\)

\(V_{ d }=\frac{ I }{ neA }=125 \times 10^{-6}\,m / s\)

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