JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
The surface of water in a water tank of cross section area \(750\,cm ^2\) on the top of a house is \(h m\). above the tap level. The speed of water coming out through the tap of cross section area \(500\,mm ^2\) is \(30\,cm / s\). At that instant, \(\frac{d h}{d t}\) is \(x \times 10^{-3} m / s\). The value of \(x\) will be \(.............\).
- A \(3\)
- B \(4\)
- C \(6\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
\(A _1 V _1= A _2 V _2\) \(750 \times 10^{-4} V _1=500 \times 10^{-6} \times 0.3\) \(V _1=\frac{500 \times 3 \times 10^{-3}}{750}\,m / s\) \(=2 \times 10^{-3}\,m / s\) \(\frac{ dh }{ dt }=-2 \times 10^{-3}\,m / s\)
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