JEE Mains · Physics · STD 12 - 13. Nuclei
A radioactive material decays by simultaneous emissions of two particles with half lives of \(1400\, years\) and \(700\, years\) respectively. What will be the time after which one third of the material remains? (Take In \(3=1.1\) ) (In \(years\))
- A \(1110\)
- B \(340\)
- C \(740\)
- D \(700\)
Answer & Solution
Correct Answer
(C) \(740\)
Step-by-step Solution
Detailed explanation
\(\text { Given } \lambda_{1}=\frac{\ell {n} 2}{700} / \text { year }, \lambda_{2}=\frac{\ell {n} 2}{1400} / \text { year }\)…
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