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JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance

A parallel plate capacitor with air between the plate has a capacitance of \(15 pF\). The separation between the plate becomes twice and the space between them is filled with a medium of dielectric constant \(3.5.\) Then the capacitance becomes \(\frac{ x }{4}\,pF\).The value of \(x\) is \(............\)

  1. A \(10.5\)
  2. B \(1.05\)
  3. C \(105\)
  4. D \(108\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(105\)

Step-by-step Solution

Detailed explanation

\(C _0=\frac{\in_0 A }{ d }=15\,pF\) \(C =\frac{ K \in_0 A }{2 d }=\frac{3.5}{2} \times 15\,pF\) \(=\frac{105}{4}\,pF\)
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