JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
A wooden block floating in a bucket of water has \(\frac{4}{5}\) of its volume submerged. When certain amount of an oil is poured into the bucket, it is found that the block is just under the oil surface with half of its volume under water and half in oil. The density of oil relative to that of water is
- A \(0.5\)
- B \(0.7\)
- C \(0.6\)
- D \(0.8\)
Answer & Solution
Correct Answer
(C) \(0.6\)
Step-by-step Solution
Detailed explanation
\(In\,{1^{st\,}}\,situation\) \({V_b}{\rho _b}g = {V_s}{\rho _w}g\) \(\frac{{{V_s}}}{{{V_b}}} = \frac{{{\rho _b}}}{{{\rho _w}}} = \frac{4}{5}\) \(...\left( i \right)\) Here \(V_b\) is volume of block \(V_s\) is submerged volume of block \({\rho _b}\) is density of block…
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