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JEE Mains · Physics · STD 11 - Gravitation
  • JEE Mains 2023
  • Medium
  • MCQ

The ratio of escape velocity of a planet to the escape velocity of earth will be:Given : Mass of the planet is \(16\) times mass of earth and radius of the planet is \(4\) times the radius of earth.

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Answer & Solution

Correct Answer

(B) \(2:1\)

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Detailed explanation

\(V_{\text {escape }}=\sqrt{\frac{2 G M}{R}}\)

\(\therefore V_{\text {escape }} \text { for planet }=\sqrt{\frac{2 G\left(16 M_E\right)}{\left(4 R_E\right)}}=2 \sqrt{\frac{2 G_E}{R_E}}\)

\(=2\left(V_{\text {escape }} \text { for Earth }\right)\)

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