JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
In the arrangement shown in figure \(a _{1}, a _{2}, a _{3}\) and \(a _{4}\) are the accelerations of masses \(m _{1}, m _{2}, m _{3}\) and \(m _{4}\) respectively. Which of the following relation is true for this arrangement?
- A \(4 a_{1}+2 a_{2}+a_{3}+a_{4}=0\)
- B \(a_{1}+4 a_{2}+3 a_{3}+a_{4}=0\)
- C \(a_{1}+4 a_{2}+3 a_{3}+2 a_{4}=0\)
- D \(2 a_{1}+2 a_{2}+3 a_{3}+a_{4}=0\)
Answer & Solution
Correct Answer
(A) \(4 a_{1}+2 a_{2}+a_{3}+a_{4}=0\)
Step-by-step Solution
Detailed explanation
Using costraint \(\sum \overrightarrow{ T } \cdot \overrightarrow{ a }=0\) \(-4 T a _{1}-2 T a _{2}- T a _{3}- T a _{4}=0\) \(4 a _{1}+2 a _{2}+ a _{3}+ a _{4}=0\)
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