JEE Mains · Physics · STD 12 - 10. Wave optics
Consider a Young’s double slit experiment as shown in figure. What should be the slit separation \(d\) in terms of wavelength \(\lambda \) such that the first minima occurs directly in front of the slit \((S_1)\)?
- A \(\frac{\lambda }{{2\left( {\sqrt 5 - 2} \right)}}\)
- B \(\frac{\lambda }{{\left( {\sqrt 5 - 2} \right)}}\)
- C \(\frac{\lambda }{{2\left( {5 - \sqrt 2 } \right)}}\)
- D \(\frac{\lambda }{{\left( {5 - \sqrt 2 } \right)}}\)
Answer & Solution
Correct Answer
(A) \(\frac{\lambda }{{2\left( {\sqrt 5 - 2} \right)}}\)
Step-by-step Solution
Detailed explanation
\(\sqrt{(2 d)^{2}+(d)^{2}}-2 d=\frac{\lambda}{2}\) \(\Rightarrow \quad(\sqrt{5}-2) d=\frac{\lambda}{2}\) \(\Rightarrow \quad d=\frac{\lambda}{2(\sqrt{5}-2)}\)
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