JEE Mains · Physics · STD 11 - System of particles and rotational motion
- JEE Mains 2020
- Hard
- MCQ
For a uniform rectangular sheet shown in the figure, the ratio of moments of inertia about the axes perpendicular to the sheet and passing through \(O\) (the centre of mass) and \(O ^{\prime}(\) corner point \()\) is

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Answer & Solution
Correct Answer
(D) \(1 / 4\)
Step-by-step Solution
Detailed explanation
Rectangular sheet
\(I _{ O }=\frac{ M }{12}\left[ L ^{2}+ B ^{2}\right]=\frac{ M }{12}\left[80^{2}+60^{2}\right]\)
\(I _{ O }= I _{0}+ Md ^{2}\{\) parallel axis theorem \(\}\)
\(\quad=\frac{ M }{12}\left[80^{2}+60^{2}\right]+ M [50]^{2}\)
\(\frac{ I _{ O }}{ I _{ O }}=\frac{ M / 12\left[80^{2}+60^{2}\right]}{\frac{ M }{12}\left[80^{2}+60^{2}\right]+ M [50]^{2}}=\frac{1}{4}\)
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