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JEE Mains · Physics · STD 11 - System of particles and rotational motion
  • JEE Mains 2020
  • Hard
  • MCQ

For a uniform rectangular sheet shown in the figure, the ratio of moments of inertia about the axes perpendicular to the sheet and passing through \(O\) (the centre of mass) and \(O ^{\prime}(\) corner point \()\) is 

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Answer & Solution

Correct Answer

(D) \(1 / 4\)

Step-by-step Solution

Detailed explanation

Rectangular sheet

\(I _{ O }=\frac{ M }{12}\left[ L ^{2}+ B ^{2}\right]=\frac{ M }{12}\left[80^{2}+60^{2}\right]\)

\(I _{ O }= I _{0}+ Md ^{2}\{\) parallel axis theorem \(\}\)

\(\quad=\frac{ M }{12}\left[80^{2}+60^{2}\right]+ M [50]^{2}\)

\(\frac{ I _{ O }}{ I _{ O }}=\frac{ M / 12\left[80^{2}+60^{2}\right]}{\frac{ M }{12}\left[80^{2}+60^{2}\right]+ M [50]^{2}}=\frac{1}{4}\)

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