JEE Mains · Physics · STD 12 - 13. Nuclei
The radius of a nucleus of mass number \(64\) is \(4.8\) fermi. Then the mass number of another nucleus having radius of \(4\) fermi is \(\frac{1000}{x}\), where \(x\) is _______.
- A \(27\)
- B \(28\)
- C \(29\)
- D \(30\)
Answer & Solution
Correct Answer
(A) \(27\)
Step-by-step Solution
Detailed explanation
\(\mathrm{R}=\mathrm{R}_0 \mathrm{~A}^{1 / 3}\) \(\mathrm{R}^3 \propto \mathrm{A}\) \(\left(\frac{4.8}{4}\right)^3=\frac{64}{\mathrm{~A}}\) \(=\frac{64}{\mathrm{~A}}=(1.2)^3\) \(\frac{64}{\mathrm{~A}}=1.44 \times 1.2\)…
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