JEE Mains · Physics · STD 11 - Motion in straight line
- JEE Mains 2024
- Hard
- Numerical
A bus moving along a straight highway with speed of \(72 \mathrm{~km} / \mathrm{h}\) is brought to halt within \(4 \mathrm{~s}\) after applying the brakes. The distance travelled by the bus during this time (Assume the retardation is uniform) is __________\(\mathrm{m}\).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(40\)
Step-by-step Solution
Detailed explanation
\(\text { Initial velocity }=u=72 \mathrm{~km} / \mathrm{h}=20 \mathrm{~m} / \mathrm{s}\)
\(\mathrm{v}=\mathrm{u}+\mathrm{at}\)
\(\Rightarrow 0=20+\mathrm{a} \times 4\)
\(\mathrm{a}=-5 \mathrm{~m} / \mathrm{s}^2\)
\(\mathrm{v}^2-\mathrm{u}^2=2 \mathrm{as}\)
\(\Rightarrow 0^2-20^2=2(-5) \mathrm{s}\)
\(\mathrm{s}=40 \mathrm{~m}\)
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