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JEE Mains · Physics · STD 11 - Motion in straight line
  • JEE Mains 2024
  • Hard
  • Numerical

A bus moving along a straight highway with speed of \(72 \mathrm{~km} / \mathrm{h}\) is brought to halt within \(4 \mathrm{~s}\) after applying the brakes. The distance travelled by the bus during this time (Assume the retardation is uniform) is __________\(\mathrm{m}\).

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Answer & Solution

Correct Answer

(B) \(40\)

Step-by-step Solution

Detailed explanation

\(\text { Initial velocity }=u=72 \mathrm{~km} / \mathrm{h}=20 \mathrm{~m} / \mathrm{s}\)

\(\mathrm{v}=\mathrm{u}+\mathrm{at}\)

\(\Rightarrow 0=20+\mathrm{a} \times 4\)

\(\mathrm{a}=-5 \mathrm{~m} / \mathrm{s}^2\)

\(\mathrm{v}^2-\mathrm{u}^2=2 \mathrm{as}\)

\(\Rightarrow 0^2-20^2=2(-5) \mathrm{s}\)

\(\mathrm{s}=40 \mathrm{~m}\)

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