JEE Mains · Physics · STD 11 - 3.2 motion in plane
A huge circular arc of length \(4.4\) \(ly\) subtends an angle \('4 {s}'\) at the centre of the circle. How long it would take for a body to complete \(4\) revolution if its speed is \(8 \;AU\;per\, second \;?\) Given : \(1\, {ly}=9.46 \times 10^{15} \,{m},\) \(\, {AU}=1.5 \times 10^{11}\, {m}\)
- A \(4.1 \times 10^{8} \,{s}\)
- B \(4.5 \times 10^{10} \,{s}\)
- C \(3.5 \times 10^{6}\, {s}\)
- D \(7.2 \times 10^{8} \,{s}\)
Answer & Solution
Correct Answer
(B) \(4.5 \times 10^{10} \,{s}\)
Step-by-step Solution
Detailed explanation
\({R}=\frac{\ell}{\theta}\) \(\text { Time }=\frac{4 \times 2 \pi {R}}{{v}}=\frac{4 \times 2 \pi}{{v}}\left(\frac{\ell}{\theta}\right)\) \(\text { put } \ell=4.4 \times 9.46 \times 10^{15}\) \({v}=8 \times 1.5 \times 10^{11}\)…
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