JEE Mains · Physics · STD 11 - Motion in plane
- JEE Mains 2021
- Hard
- MCQ
A huge circular arc of length \(4.4\) \(ly\) subtends an angle \('4 {s}'\) at the centre of the circle. How long it would take for a body to complete \(4\) revolution if its speed is \(8 \;AU\;per\, second \;?\) Given : \(1\, {ly}=9.46 \times 10^{15} \,{m},\) \(\, {AU}=1.5 \times 10^{11}\, {m}\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(4.5 \times 10^{10} \,{s}\)
Step-by-step Solution
Detailed explanation
\({R}=\frac{\ell}{\theta}\)
\(\text { Time }=\frac{4 \times 2 \pi {R}}{{v}}=\frac{4 \times 2 \pi}{{v}}\left(\frac{\ell}{\theta}\right)\)
\(\text { put } \ell=4.4 \times 9.46 \times 10^{15}\)
\({v}=8 \times 1.5 \times 10^{11}\)
\(\theta=\frac{4}{3600} \times \frac{\pi}{180} {rad}\)
\(\text { we get time }=4.5 \times 10^{10} {sec}\)
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