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JEE Mains · Physics · STD 11 - Motion in plane
  • JEE Mains 2021
  • Hard
  • MCQ

A huge circular arc of length \(4.4\) \(ly\) subtends an angle \('4 {s}'\) at the centre of the circle. How long it would take for a body to complete \(4\) revolution if its speed is \(8 \;AU\;per\, second \;?\) Given : \(1\, {ly}=9.46 \times 10^{15} \,{m},\) \(\, {AU}=1.5 \times 10^{11}\, {m}\)

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Answer & Solution

Correct Answer

(B) \(4.5 \times 10^{10} \,{s}\)

Step-by-step Solution

Detailed explanation

\({R}=\frac{\ell}{\theta}\)

\(\text { Time }=\frac{4 \times 2 \pi {R}}{{v}}=\frac{4 \times 2 \pi}{{v}}\left(\frac{\ell}{\theta}\right)\)

\(\text { put } \ell=4.4 \times 9.46 \times 10^{15}\)

\({v}=8 \times 1.5 \times 10^{11}\)

\(\theta=\frac{4}{3600} \times \frac{\pi}{180} {rad}\)

\(\text { we get time }=4.5 \times 10^{10} {sec}\)

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