JEE Mains · Physics · STD 12 - 3. current electricity
In the given figure, the \(emf\) of the cell is \(2.2\, {V}\) and if internal resistance is \(0.6\, \Omega\). Calculate the power dissipated in the whole circuit: (in \(W\))
- A \(1.32\)
- B \(0.65\)
- C \(2.2\)
- D \(4.4\)
Answer & Solution
Correct Answer
(C) \(2.2\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{R_{e q}}=\frac{1}{4}+\frac{1}{8}+\frac{1}{12}+\frac{1}{6}=\frac{6+3+2+4}{24}=\frac{15}{24}\) \(R_{e q}=\frac{24}{15}=1.6 \Rightarrow R_{T}=1.6+0.6=2.2 \,\Omega\) \(P=\frac{V^{2}}{R_{T}}=\frac{(2.2)^{2}}{2.2}=2.2 \,{W}\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- Which one of the following is not a measurable quantity ?JEE Mains 2026 Medium
- particle moves with simple harmonic motion in a straight line. In first \(\tau\ s\), after starting from rest it travels a distance \(a\), and in next \(\tau\ s\) it travels \(2a\), in same direction, thenJEE Mains 2014 Hard
- An object is placed at a distance of \(12 \,{cm}\) from a convex lens. A convex mirror of focal length \(15 \,{cm}\) is placed on other side of lens at \(8 \,{cm}\) as shown in the figure. Image of object coincides with the object.When the convex mirror is removed, a real and inverted image is formed at a position. The distance of the image from the object will be ..... \((cm)\)
JEE Mains 2021 Hard - A particle starts from origin at \(t=0\) with a velocity \(5 \hat{i} \mathrm{~m} / \mathrm{s}\) and moves in \(x-y\) plane under action of a force which produces a constant acceleration of \((3 \hat{i}+2 \hat{j}) \mathrm{m} / \mathrm{s}^2\). If the \(x\)-coordinate of the particle at that instant is \(84 \mathrm{~m}\), then the speed of the particle at this time is \(\sqrt{\alpha} \mathrm{m} / \mathrm{s}\). The value of \(\alpha\) is___________.JEE Mains 2024 Hard
- A small point of mass \(m\) is placed at a distance \(2 R\) from the centre ' \(O^{\prime}\) of a big uniform solid sphere of mass M and radius R . The gravitational force on ' m ' due to M is \(\mathrm{F}_1\). A spherical part of radius \(\mathrm{R} / 3\) is removed from the big sphere as shown in the figure and the gravitational force on m due to remaining part of M is found to be \(\mathrm{F}_2\). The value of ratio \(\mathrm{F}_1: \mathrm{F}_2\) is _______.
JEE Mains 2025 Hard - A physical quantity \(y\) is represented by the formula \(y=m^{2}\, r^{-4}\, g^{x}\,l^{-\frac{3}{2}}\). If the percentage error found in \(y, m, r, l\) and \(g\) are \(18,1,0.5,4\) and \(p\) respectively, then find the value of \(x\) and \(p\).JEE Mains 2021 Medium
More PYQs from JEE Mains
- Let \(\Delta\) be the area of the region \(\left\{( x , y ) \in R ^2: x ^2+ y ^2 \leq 21, y ^2 \leq 4 x , x \geq 1\right\}\). Then \(\frac{1}{2}\left(\Delta-21 \sin ^{-1} \frac{2}{\sqrt{7}}\right)\) is equal toJEE Mains 2023 Hard
- Two vectors \(\overrightarrow{{X}}\) and \(\overrightarrow{{Y}}\) have equal magnitude. The magnitude of \((\overrightarrow{{X}}-\overrightarrow{{Y}})\) is \({n}\) times the magnitude of \((\overrightarrow{{X}}+\overrightarrow{{Y}})\). The angle between \(\overrightarrow{{X}}\) and \(\overrightarrow{{Y}}\) is -JEE Mains 2021 Hard
- A series \(LR\) circuit connected with an ac source \(E=(25 \sin 1000 t)\ V\) has a power factor of \(\frac{1}{\sqrt{2}}\). If the source of emf is changed to \(E=(20 \sin 2000 t)\ V,\) the new power factor of the circuit will be _______.JEE Mains 2024 Hard
- Net gravitational force at the centre of a square is found to be \( F_{1} \) when four particles having mass M, 2M, 3M and 4M are placed at the four corners of the square as shown in figure and it is \( F_{2} \) when the positions of 3M and 4M are interchanged. The ratio \( \frac{F_{1}}{F_{2}} \) is \( \frac{\alpha}{\sqrt{5}} \). The value of \( \alpha \) is __________ .
JEE Mains 2026 Easy - The values of \(\mathrm{m}, \mathrm{n}\), for which the system of equations \( x+y+z=4 \) \( 2 x+5 y+5 z=17 \) \( x+2 y+m z=n\) has infinitely many solutions, satisfy the equation :JEE Mains 2024 Hard
- The area of the region : \(R =\left\{( x , y ): 5 x ^{2} \leq y \leq 2 x ^{2}+9\right\}\) is ........ \(square\, units\)JEE Mains 2021 Hard