ExamBro
ExamBro
JEE Mains · Physics · STD 12 -Electromagnetic induction
  • JEE Mains 2023
  • Medium
  • MCQ

A conducting loop of radius \(\frac{10}{\sqrt{\pi}}\,cm\) is placed perpendicular to a uniform magnetic field of \(0.5\,T\). The magnetic field is decreased to \(zero\) in \(0.5\,s\) at a steady rate. The induced emf in the circular loop at \(0.25\,s\) is:

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(emf =10\,mV\)

Step-by-step Solution

Detailed explanation

\(EMF =\frac{ d \phi}{ dt }=\frac{ BA -0}{ t }\)

\(A =\pi r ^2=\pi\left(\frac{0.1^2}{\pi}\right)=0.01\)

\(B =0.5\)

\(EMF =\frac{(0.5)(0.01)}{0.5}=0.01\,V =10\,mV\)

Same subject
Explore more questions on app