ExamBro
ExamBro
JEE Mains · Physics · STD 12 - Electric charges and fields
  • JEE Mains 2022
  • Medium
  • Numerical

The volume charge density of a sphere of radius \(6 \,m\) is \(2 \,\mu cm ^{-3}\). The number of lines of force per unit surface area coming out from the surface of the sphere is \(....\times 10^{10}\, NC ^{-1}\).  [Given : Permittivity of vacuum  \(\left.\epsilon_{0}=8.85 \times 10^{-12} C ^{2} N ^{-1}- m ^{-2}\right]\)

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(C) \(45\)

Step-by-step Solution

Detailed explanation

No. of electric field lines per unit area \(=\) electric field.

\(E =\frac{\rho r}{3 \epsilon_{0}}, \text { for } r=R\)

\(E=\frac{\rho R}{3 \epsilon_{0}}=\frac{2 \times 6}{3 \times 8.85 \times 10^{-12}}=0.45 \times 10^{12}\,NC ^{-1}\)

\(=45 \times 10^{10}\,N / C\)

Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app